Briscola code is still in progress... until... ?

Here we are again having fun making code for a card game... will we ever finish it, or will we change it a lot of time never reaching a goal? Who knows... here is the code at the moment... 

print("Let's play BRISCOLA")

from random import shuffle

cl = '♦♣♠♥'
nm = range(1,11)
cds = [str(n)+c for n in nm for c in cl]

def pop(x=1):
    return [cds.pop() for i in range(x)]

shuffle(cds)

p1,p2 = pop(3),pop(3)       # pick the cards 1st time
bsc = cds.pop()
print(p1,"|",p2,"|",bsc,"bsc")
pcval = {1:11,2:0,3:10,4:0,5:0,6:0,7:0,8:2,9:3,10:4}
top = [2,4,5,6,7,8,9,10,3,1]
cl2 = list(cl)
cl2.remove(bsc[-1])
# Lista delle carte da tirare in ordine di preferenza per la prima mossa
defense = [str(x)+c for x in top[:9] for c in cl2]+[str(x)+bsc[-1] for x in top[:9]]+['1'+bsc[-1]] +[str(x)+c for x in top[9:] for c in cl2]+['3'+bsc[-1]]

def num(x):
    return int(x[:-1])

def col(x):
    return x[-1]
    
def val(card):
    return pcval[int(card[:-1])]

def attack(tbx):
    att = [x+col(tbx) for x in ['1','3','10','9'] if int(x) > val(tbx)]
    att += [str(x)+c for x in top[:7] for c in cl if c!=col(bsc)]
    att += [str(x)+col(bsc) for x in top]
    att += [str(x)+c for x in (3,1) for c in cl if c!=col(bsc)]
    # print(att)
    return att

def attack2(tbx):
    latt = [x for x in range(3)]
    return latt
    

def mode(px,list_da):
    'algoritmo di risposta'
    for i in list_da:
        if i in px:
            px.remove(i)
            print(i)
            break
    return i

def move1():
    global tb1
    tb1 = mode(p1,defense)


def move2():
    global tb2
    tb2 = mode(p2,attack(tb1))
    
    # Colore diverso
    if col(tb1)!=col(tb2) and col(tb2)!=col(bsc):
        print("P2 ha perso")
    
    # Stesso colore
    else:
        if val(tb1)==val(tb2):
            if num(tb1)>num(tb2):
                print("Stesso colore Ha vinto p1",val(tb1)+val(tb2))
            else:
                print("Stesso colore Ha vinto p2")
        else:
            if val(tb1)>val(tb2):
                print(val(tb1),val(tb2),"Stesso colore Ha vinto p1")
            else:
                print(val(tb1)+val(tb2),"Stesso colore punti vinti da p2")



move1()                    
move2()  

Let's play BRISCOLA
['3♣', '9♠', '1♣'] | ['4♠', '7♣', '7♦'] | 4♥ bsc
9♠
4♠
3 0 Stesso colore Ha vinto p1